A jar contains a gas and few drops of water at T K. The pressure … - Vidyadip

MCQ

A jar contains a gas and few drops of water at $T K.$ The pressure in the jar is $830 \,mm$ of mercury. The temperature of jar is reduced by $1\%.$ The saturated vapour pressure of water at the two temperatures are $30 \,mm$ and $ 25\, mm$ of mercury. Then the new pressure in the jar will be ..... $mm$ of $Hg$

A
$917$
B
$717$
✓
$817$
D
None of these

✓

Answer

Correct option: C.

$817$

c
Pressure in the jar $=830 \; mm$ of $Hg$.

Pressure of moisture $=30 \; mm$ of $Hg$.

Pressure of dry gas $=830-30=800 \; mm$ of $Hg$.

Since the volume is constant and the temperature is changing, using the ideal gas equation,

$\frac{ T _{1}}{ P _{1}}=\frac{ T _{2}}{ P _{2}} \Rightarrow \frac{ T _{1}}{800}=\frac{0.99 T _{1}}{ P _{2}} \Rightarrow P _{2}=0.99 \times 800=792 \; mm$ of $Hg$

Therefore, the total pressure $=792+25=817 \; mm$ of $Hg$.

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