
The lighter liquid floats over heavier liquid. Therefore
we can conclude that ${\rho _1} < {\rho _2}$
Also ${\rho _3} < {\rho _2}$ otherwise the ball would have sink to the bottom of the jar.
Also ${\rho _3} < {\rho _1}$ otherwise the ball would have floated in liquid $1$. From the above discussion we conclude that
${\rho _1} < {\rho _3} < {\rho _2}.$
|Take atmospheric pressure $=1.0 \times 10^5 \mathrm{~N} / \mathrm{m}^2$, density of water $=1000 \mathrm{~kg} / \mathrm{m}^3$ and $g=10 \mathrm{~m} / \mathrm{s}^2$. Neglect any effect of surface tension.]

(Take acceleration due to gravity $=10\,ms ^{-2}$ )
[take $\rho_{water} \left.=1000 \;\mathrm{kg} / \mathrm{m}^{3}\right]$
( $g$ $ =$ acceleration due to gravity $= 10$ $ ms^{^{-2}} )$