
For hole ' $A$ '
Velocity of efflux $=\sqrt{2 g\left(x+h^{\prime}\right)}$
$R=2\left[\left(x+h^1\right) h\right]^{1 / 2} \quad \ldots (1)$
For hole ' $B$ '
Velocity of efflux $=\sqrt{2 g h^{\prime}}$
$R=2\left[h^{\prime}(x+h)\right]^{1 / 2} \quad \ldots (2)$
Equating $(a)$ and $(b)$
We get
$2\left[\left(x+h^{\prime}\right) h\right]^{1 / 2}=2\left[h^{\prime}(x+h)\right]^{1 / 2}$
$\Rightarrow \left(x+h^{\prime}\right) h=h^{\prime}(x+h)$
$\Rightarrow h=h^{\prime}$
$\Rightarrow \frac{h^{\prime}}{h}=1$

(The coefficient of viscosity of water is $9.8 \times 10^{-6}$ $\left.\mathrm{N} \mathrm{s} / \mathrm{m}^2\right)$

