A large concave mirror has a radius of curvature of 1.5m. A person stands 10m in front of the mirror. Where is the person’s image?
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R = -1.5cm (concave mirror) u = -10cm$\text{f}=\frac{\text{R}}{2}=\frac{1.5}{2}=0.75\text{cm}$
$\frac{1}{\text{v}}+\frac{1}{\text{u}}=\frac{1}{\text{f}}$
$\Rightarrow \frac{1}{\text{v}}+\frac{1}{\text{(-10)}}=\frac{1}{(-0.75)}$
$\Rightarrow \frac{1}{\text{v}}=\frac{1}{10}-\frac{1}{0.75}=\frac{1}{10}-\frac{100}{75}$
$\frac{1}{10}-\frac{4}{3}=\frac{3-40}{30}=-\frac{37}{30}$
$\therefore\text{v}=-\frac{30}{37}=-0.81\text{cm}$
The person's image will be 0.81m in frond of concave mirror.
$\frac{1}{\text{v}}+\frac{1}{\text{u}}=\frac{1}{\text{f}}$
$\Rightarrow \frac{1}{\text{v}}+\frac{1}{\text{(-10)}}=\frac{1}{(-0.75)}$
$\Rightarrow \frac{1}{\text{v}}=\frac{1}{10}-\frac{1}{0.75}=\frac{1}{10}-\frac{100}{75}$
$\frac{1}{10}-\frac{4}{3}=\frac{3-40}{30}=-\frac{37}{30}$
$\therefore\text{v}=-\frac{30}{37}=-0.81\text{cm}$
The person's image will be 0.81m in frond of concave mirror.
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