A light pointer fixed to one prong of a tuning fork touches a ver… - Vidyadip

MCQ

A light pointer fixed to one prong of a tuning fork touches a vertical plate. The fork is set vibrating and the plate is allowed to fall freely. If eight oscillations are counted when the plate falls through $10 \mathrm{~cm}$, the frequency of the tuning fork is

A
$360 \mathrm{~Hz}$
B
$280 \mathrm{~Hz}$
C
$560 \mathrm{~Hz}$
✓
$56 \mathrm{~Hz}$

✓

Answer

Correct option: D.

$56 \mathrm{~Hz}$

Time of fall $=\sqrt{\frac{2 h}{g}}=\sqrt{\frac{2 \times 10}{1000}}=\frac{1}{\sqrt{50}}$
In this time number of oscillations areeight So time for1 oscillation $(=\frac{1}{8}\sqrt{50})$
Frequency $=8 \sqrt{50} \mathrm{~Hz}=56 \mathrm{~Hz}$

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