MCQ
A light source of wavelength $\lambda$ illuminates a metal surface and electrons are ejected with maximum kinetic energy of 2 eV . If the same surface is illuminated by a light source of wavelength $\frac{\lambda}{2}$, then the maximum kinetic energy of ejected electrons will be (The work function of metal is 1 eV )
  • A
    2 eV
  • B
    6 eV
  • 5 eV
  • D
    3 eV

Answer

Correct option: C.
5 eV
(C) 5 eV
$ \begin{array}{l} \frac{hc}{\lambda}=\phi+eV \Rightarrow \frac{hc}{\lambda}=1+2=3 eV \ldots(1)\\ \frac{hc}{\lambda / 2}=6=1+k_{\max } \therefore k_{\max }=5 eV \end{array} $

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