A black body is at a temperature of $2880\;K$. The energy of radiation emitted by this object with wavelength between $499\;nm$ and $500\;nm$ is ${U_1}$, between $999\;nm$ and $1000\;nm$ is ${U_2}$ and between $1499\;nm$ and $1500\;nm$ is ${U_3}$. The Wein's constant $b = 2.88 \times {10^6}\;nm\,K$. Then
IIT 1998, Medium
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(d) Wein's displacement law is ${\lambda _m}T = b$
==> ${\lambda _m} = \frac{b}{T} = \frac{{2.88 \times {{10}^6}}}{{2880}} = 1000\,nm.$
Energy distribution with wavelength will be as follows
From the graph it is clear that $U_2 > U_1$.
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