A spring is stretched by $5 \,\mathrm{~cm}$ by a force $10 \,\mathrm{~N}$. The time period of the oscillations when a mass of $2 \,\mathrm{~kg}$ is suspended by it is :(in $s$)
NEET 2021, Medium
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$\mathrm{F}=\mathrm{K} \mathrm{x}$
$10=\mathrm{K} \times 0.05$
$\mathrm{~K}=\frac{1000}{5}=200$
$\mathrm{~T}=2 \pi \sqrt{\frac{\mathrm{m}}{\mathrm{k}}}=2 \pi \sqrt{\frac{2}{200}}$
$=\frac{2 \pi}{10}=\frac{6.28}{10}$
$=.628\, \mathrm{~s}$
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