A liquid cools from $50^oC$ to $45^oC$ in 5 minutes and from $45 ^o C$ to $41.5 ^o C$ in the next $5$ minutes. The temperature of the surrounding is ...... $^oC$
Diffcult
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(d)$\frac{{50 - 45}}{5} = K\left( {\frac{{50 + 45}}{2} - {\theta _0}} \right)$ ….$.(i)$
$\frac{{45 - 41.5}}{5} = K\left( {\frac{{45 + 41.5}}{2} - {\theta _0}} \right)$…..$(ii)$
Solving equation $(i)$ and $(ii)$ we set ${\theta _0} = 33.3\;^\circ C$.
$\frac{{45 - 41.5}}{5} = K\left( {\frac{{45 + 41.5}}{2} - {\theta _0}} \right)$…..$(ii)$
Solving equation $(i)$ and $(ii)$ we set ${\theta _0} = 33.3\;^\circ C$.
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