A liquid flows in a tube from left to right as shown in figure. ${A_1}$ and ${A_2}$ are the cross-sections of the portions of the tube as shown. Then the ratio of speeds ${v_1}/{v_2}$ will be
  • A${A_1}/{A_2}$
  • B${A_2}/{A_1}$
  • C$\sqrt {{A_2}} /\sqrt {{A_1}} $
  • D$\sqrt {{A_1}} /\sqrt {{A_2}} $
Medium
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