a
$P _{1}=\rho gd + P _{0}=3 \times 10^{5} Pa$
$\therefore \rho gd =2 \times 10^{5} Pa$
$P _{2}=2 \rho gd + P _{0}$
$=4 \times 10^{5}+10^{5}=5 \times 10^{5} Pa$
$\%$increase $=\frac{ P _{2}- P _{1}}{ P _{1}} \times 100$
$=\frac{5 \times 10^{5}-3 \times 10^{5}}{3 \times 10^{5}} \times 100=\frac{200}{3} \%$