An incompressible liquid flows through a horizontal tube as shown in the following fig. Then the velocity $ v$ of the fluid is .......$m/s$
Medium
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(c)If the liquid is incompressible then mass of liquid entering through left end, should be equal to mass of liquid coming out from the right end.
$\therefore \;M = {m_1} + {m_2}$ ==> $A{v_1} = A{v_2} + 1.5A\,.\,v$
==> $A \times 3 = A \times 1.5 + 1.5A\,.\,v$ ==> $v = 1\;m/s$
$\therefore \;M = {m_1} + {m_2}$ ==> $A{v_1} = A{v_2} + 1.5A\,.\,v$
==> $A \times 3 = A \times 1.5 + 1.5A\,.\,v$ ==> $v = 1\;m/s$
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