A liquid is kept in a cylindrical vessel which rotated along its axis. The liquid rises at the sides. If the radius of the vessel is $0.05\,m$ and the speed of rotation is $2\,rev/s$ , The difference in the height of the liquid at the centre of the vessel and its sides will be .............. $\mathrm{cm}$ $(\pi ^2 = 10)$
Diffcult
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$y = \frac{{{\omega ^2}{r^2}}}{{2g}}$
Put values and get $y = 2\,cm$
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