A square plate of $0.1 \;m$ side moves parallel to a second plate with a velocity of $ 0.1\; m/s$, both plates being immersed in water. If the viscous force is $0.002\; N$ and the coefficient of viscosity is $ 0.01 $ poise, distance between the plates in $m$ is
Medium
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(d) $A = {(0.1)^2} = 0.01{m^2}$, $\eta = 0.01\,\;Poise = 0.001\;\;decapoise$ $(M.K.S.$ unit),
$dv = 0.1 m/s $ and $ F = 0.002 N$
$F = \eta A\frac{{dv}}{{dx}}$ $\therefore \;\;dx = \frac{{\eta Adv}}{F} = \frac{{0.001 \times 0.01 \times 0.1}}{{0.002}} = 0.0005m$.
$dv = 0.1 m/s $ and $ F = 0.002 N$
$F = \eta A\frac{{dv}}{{dx}}$ $\therefore \;\;dx = \frac{{\eta Adv}}{F} = \frac{{0.001 \times 0.01 \times 0.1}}{{0.002}} = 0.0005m$.
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