A long straight wire carries a current of $35\; A$. What is the magnitude of the field $B$ at a point $20\; cm$ from the wire?
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Current in the wire, $I=35 \,A$
Distance of a point from the wire, $r=20 \,cm =0.2 \,m$
Magnitude of the magnetic field at this point is given as:
$B=\frac{\mu_{0}}{4 \pi} \frac{2 I}{r}$
Where,
$\mu_{0}=$ Permeability of free space $=4 \pi \times 10^{-7} \,T\,m\, A ^{-1}$
$B=\frac{4 \pi \times 10^{-7} \times 2 \times 35}{4 \pi \times 0.2}$
$=3.5 \times 10^{-5} \;T$
Hence, the magnitude of the magnetic field at a point $20\, cm$ from is $3.5 \times 10^{-5} \;T$
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