Distance of a point from the wire, $r=20 \,cm =0.2 \,m$

Magnitude of the magnetic field at this point is given as:

$B=\frac{\mu_{0}}{4 \pi} \frac{2 I}{r}$

Where,

$\mu_{0}=$ Permeability of free space $=4 \pi \times 10^{-7} \,T\,m\, A ^{-1}$

$B=\frac{4 \pi \times 10^{-7} \times 2 \times 35}{4 \pi \times 0.2}$

$=3.5 \times 10^{-5} \;T$

Hence, the magnitude of the magnetic field at a point $20\, cm$ from is $3.5 \times 10^{-5} \;T$