A long straight wire of radius a carries a steady current I. The current is uniformly distributed across its cross section. The ratio of the magnetic field at $\frac{a}{2}$ and $2$a from axis of the wire is:
JEE MAIN 2024, Diffcult
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$\mathrm{B}_1 2 \pi \frac{\mathrm{a}}{2}=\mu_0 \frac{\mathrm{I}}{4}$
$\mathrm{~B}_1=\frac{\mu_0 \mathrm{I}}{4 \pi \mathrm{a}}$
$\mathrm{B}_2 2 \pi 2 \mathrm{a}=\mu_0 \mathrm{I}$
$\mathrm{B}_2=\frac{\mu_{\mathrm{v}} \mathrm{I}}{4 \pi \mathrm{a}}$
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