A longitudinal wave is represented by $x =10 \sin 2 \pi\left( nt -\frac{ x }{\lambda}\right) \,cm$. The maximum particle velocity will be four times the wave velocity if the determined value of wavelength is equal to .....................
JEE MAIN 2022, Medium
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$V _{ P } \max =4 V _{\text {wave }}$
$\omega A =4\left(\frac{\omega}{ k }\right) \Rightarrow A =\frac{4 \lambda}{2 \pi}$
$\lambda=\frac{2 \pi A }{4} \Rightarrow \frac{20 \pi}{4} \Rightarrow 5 \pi$
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