Ten tuning forks are arranged in increasing order of frequency in such a way that any two nearest tuning forks produce $4$ beats/sec. The highest frequency is twice of the lowest. Possible highest and the lowest frequencies are
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(d) Using $n_{Last} = n_{First} + (N -1)x$
where $N =$ Number of tuning fork in series
$x =$ beat frequency between two successive forks
$==> 2n = n + (10 -1) × 4 n = 36 Hz$
$\therefore$ $ n_{First} = 36 Hz$ and $n_{Last} = 2 × n_{First} = 72 Hz$
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