A man stands in front of a hillock and fires a gun. He hears an echo after $1.5\, sec$. The distance of the hillock from the man is ...... $m$ (velocity of sound in air is $330\, m/s$)
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(b) If $d$ is the distance between man and reflecting surface of sound then for hearing echo
$2d = v \times t \Rightarrow d = \frac{{330 \times 1.5}}{2} = 247.5\,m$
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${z_1} = a\cos (kx - \omega \,t)$.....$(A)$
${z_2} = a\cos (kx + \omega \,t)$.....$(B)$
${z_3} = a\cos (ky - \omega \,t)$..... $(C)$