MCQ
A man throws balls with the same speed vertically upwards one after the other at an interval of 2 seconds. What should be the speed of the throw so that more than two balls are in the sky at any time (Given $g=9.8 m / s ^2$ )
  • A
    At least $0.8 m / s$
  • B
    Any speed less than $19.6 m / s$
  • C
    Only with speed $19.6 m / s$
  • More than $19.6 m / s$

Answer

Correct option: D.
More than $19.6 m / s$
(d) Interval of ball throw $=2 \ \mathrm{sec}$.If we want that minimum three (more than two )ball remain in air then time of flight of first ball must be greater than $4\mathrm{sec}$
$T>4 \mathrm{sec} $ $\frac{2 u}{g} >4\mathrm{sec} \Rightarrow u > 19.6\mathrm{~m} \mathrm{s}$ for $u=19.6$.
First ball will just strike the ground (in sky) Second N ball will (in sky)Third ball will be at point of projection or at ground (not in sky) (a) The distance covered by the ball during the last $t$ seconds of its upward motion $=$ Distance covered by it in first $t$ seconds of its downward motionFrom $h=u t+\frac{1}{2} g t^2$

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