$\text{x}=\text{A}\cos(\omega\text{t}+\theta)$
where,
A is the amplitude
x is the displacement
$\theta$ is the phase constant
Velcoity, $\text{v}=\frac{\text{dx}}{\text{dt}}=-\text{A}\omega\sin(\omega\text{t}+\theta)$
At, t = 0, x = x0
$\text{x}_0=\text{A}\cos\theta=\text{x}_0\ .....(\text{i})$
and, $\frac{\text{dx}}{\text{dt}}=-v_0=\text{A}\omega\sin\theta$
$\text{A}\sin\theta=\frac{v_0}{\omega}\ ....(\text{ii})$
Squaring and adding equations (i) and (ii), we get:
$\text{A}^2(\cos^2\theta+\sin^2\theta)=\text{x}_0^2+\Big(\frac{v_0^2}{\omega^2}\Big)$
$\therefore\ \text{A}=\sqrt{\text{x}_0^2+\Big(\frac{v_0}{\omega}\Big)^2}$
Hence, the amplitude of the resulting oscillation is $\text{x}_0^2+\Big(\frac{v_0}{\omega}\Big)^2.$
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