A mass M, attached to a horizontal spring, executes S.H.M. with amplitude A_1. When the mass M passes through its mean position then a smaller

Q: A mass $M$, attached to a horizontal spring, executes S.H.M. with amplitude $A_1$. When the mass $M$ passes through its mean position then a smaller mass $m$ is placed over it and both of them move together with amplitude $A_2$. The ratio of $\frac{{{A_1}}}{{{A_2}}}$ is

d The net force becomes zero at the mean point. Therefore, linear momentum must be conserved. $\therefore \quad M v_{1}=(M+m) v_{2}$ $M A_{1} \sqrt{\frac{k}{M}}=(M+m) A_{2} \sqrt{\frac{k}{m+M}} \therefore \quad(V=A \sqrt{\frac{k}{M}})$ $A_{1} \sqrt{M}=A_{2} \sqrt{M+m} \quad \therefore \frac{A_{1}}{A_{2}}=\sqrt{\frac{m+M}{M}}$

SECTION - A [PHYSICS - MCQ]

GSEB - English Medium

A mass $M$, attached to a horizontal spring, executes S.H.M. with amplitude $A_1$. When the mass $M$ passes through its mean position then a smaller mass $m$ is placed over it and both of them move together with amplitude $A_2$. The ratio of $\frac{{{A_1}}}{{{A_2}}}$ is

A$\frac{M}{{M + m}}\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;$
B$\;\frac{{M + m}}{M}$
C${\left( {\;\frac{M}{{M + m}}} \right)^{\frac{1}{2}}}$
D${\left( {\;\frac{{M + m}}{M}} \right)^{\frac{1}{2}}}$

AIEEE 2011, Diffcult

STD 11 Science
NEET
STD 11 - 13. oscillations
Physics

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