b
$R=\frac{\rho \ell}{A}=\frac{\rho \ell}{(V / \ell)}=\frac{\rho \ell^{2}}{V} \quad(V \rightarrow \text { Volume of wire })$
$\Rightarrow$ Final resistance $=3 \times(\mathrm{B})^{2}=12 \,\Omega$
$\begin{aligned} \mathrm{R}_{\mathrm{eq}} &=2\, \Omega \| 10\, \Omega \\ &=\frac{5}{3} \,\Omega \end{aligned}$
