$\Delta T=100 K$
$L=0.54 m$
Rate = latent heat of fusion Itimes mass melted per sec $=333.5 \times(1 / 33) J / g$
putting values $\Longrightarrow \frac{K \times 9 \times 10^{-4} \times 100}{0.54}=333.5 \times(1 / 33)$
$K=60.63 W /(m K)$
rounding off, $K=60 \mathrm{W} /(\mathrm{mK})$

Then, for the arrangement as shown in the figure. The value of temperature $T$ of the steel - copper junction in the steady state will be ........... $^{\circ} C$
