MCQ
A metallic spherical shell has an inner radius $R_1$ and outer radius $R_2$. A charge $Q$ is placed at the centre of the spherical cavity. What will be surface charge density on the inner surface
  • A
    $\frac{Q}{{4\pi R_1^2}}$
  • $ - \frac{Q}{{4\pi R_1^2}}$
  • C
    $\frac{Q}{{4\pi R_2^2}}$
  • D
    $ - \frac{Q}{{4\pi R_2^2}}$

Answer

Correct option: B.
$ - \frac{Q}{{4\pi R_1^2}}$
b
A charge $\mathrm{Q}$ is placed at the centre of the spherical cavity. So, the charge induced at the inner surface of the sphere will be -Q and at outer surface of the sphere is $+Q$.

The surface charge density on the inner surface $\sigma_{1}=\frac{\text { Charge }}{\text { Area }}=\frac{-Q}{4 \pi R_{1}^{2}}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free