A meter bridge is set-up as shown, to determine an unknown resistance ' $X$ ' using a standard $10$ ohm resistor. The galvanometer shows null point when tapping-key is at $52 \ cm$ mark. The end-corrections are $1 \ cm$ and $2 \ cm$ respectively for the ends $A$ and $B$. The determined value of ' $X$ ' is
A$10.2 \ ohm$
B$10.6 \ ohm$
C$10.8 \ ohm$
D$11.1 \ ohm$
IIT 2011, Diffcult
Download our app for free and get started
B$10.6 \ ohm$
b Using the condition for balanced Wheatstone bridge, we get
$\frac{X}{10}=\frac{(52+1) cm }{(100-52+2) cm }=\frac{53}{50}$
or $X=\frac{53 \times 10}{50}=10.6 \ \Omega$
Download our app
and get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
$12$ cells each having same $emf$ are connected in series with some cells wrongly connected. The arrangement is connected in series with an ammeter and two cells which are in series. Current is $3 \,A$ when cells and battery aid each other and is $2\, A$ when cells and battery oppose each other. The number of cells wrongly connected is
What amount of heat will be generated in a coil of resistance $R$ due to a charge $q$ passing through it if the current in the coil decreases to zero uniformly during a time interval $\Delta t$
Thousand cells of same emf $E$ and same internal resistance $r$ are connected in series in same order without an external resistance. The potential drop across $399$ cells is found to be ......... $E$