A milliammeter of range $10\, mA$ has a coil of resistance $1 \,\Omega$. To use it as voltmeter of range $10\, volt$, the resistance that must be connected in series with it, will be ............. $\Omega $
Medium
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(a) $R = \frac{V}{{{i_g}}} - G = \frac{{10}}{{10 \times {{10}^{ - 3}}}} - 1 = 999\,\Omega $.
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