The current sensitivity of a moving coil galvanometer increases by $20 \%$ when its resistance is doubled. Calculate, by what factor does the voltage sensitivity change?
Medium
Download our appand get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Similar Questions
- 1An electron is moving along the positive $X$-axis. You want to apply a magnetic field for a short time so that the electron may reverse its direction and move parallel to the negative $X$-axis. This can be done by applying the magnetic field alongView Solution
- 2View SolutionIf the radius of a coil is halved and the number of turns doubled, then the magnetic field at the centre of the coil, for the same current will
- 3The resistance of a galvanometer is $25\, ohm$ and it requires $50\,\mu A$ for full deflection. The value of the shunt resistance required to convert it into an ammeter of $5\, amp$ isView Solution
- 4A tightly wound $100$ turns coil of radius $10 \mathrm{~cm}$ carries a current of $7 \mathrm{~A}$. The magnitude of the magnetic field at the centre of the coil is (Take permeability of free space as $4 \pi \times 10^{-7} \mathrm{SI}$ units):View Solution
- 5A square shaped wire loop of mass $m$, resistance $R$ and side $a$ moving speed $v_{0}$, parallel to the $X$-axis, enters a region of uniform magnetic field $B$, which is perpendicular to the plane of the loop. The speed of the loop changes with distance $x(x < a)$ in the field, asView Solution
- 6Three long, straight and parallel wires carrying currents are arranged as shown in figure. The force experienced by $10\, cm$ length of wire $Q$ isView Solution
- 7The current in the windings of a toroid is $2.0\,A$. There are $400\,turns$ and the mean circumferential length is $40\,cm$. If the inside magnetic field is $1.0\,T,$ the relative permeability is near toView Solution
- 8A part of a long wire carrying a current $i$ is bent into a circle of radius $r$ as shown in figure. The net magnetic field at the centre $O$ of the circular loop isView Solution
- 9A straight conductor carrying current $i$ splits into two parts as shown in the figure. The radius of the circular loop is $R$. The total magnetic field at the centre $P$ of the loop is$......$View Solution
- 10The field normal to the plane of a wire of $n$ turns and radius $r$ which carries a current $i$ is measured on the axis of the coil at a small distance $h$ from the centre of the coil. This is smaller than the field at the centre by the fractionView Solution