MCQ
A mixture of gases contains $H_2$ and $O_2$ gases in the ratio of $1 : 4\ (w/w).$ What is the molar ratio of the two gases in the mixture?
  • A
    $16 : 1$
  • B
    $2 : 1$
  • C
    $1 : 4$
  • $4 : 1$

Answer

Correct option: D.
$4 : 1$
d
Let the mass of $\mathrm{H}_{2}$ gas be $\mathrm{x} \mathrm{g}$ and mass of $\mathrm{O}_{2}$ gas $4 \mathrm{xg}$ Molar

$\quad \quad \mathrm{H}_{2}: \mathrm{O}_{2}$

mass $2: 32$

i.e. $1: 16$

therefore, Molar ratio $=\frac{n_{\mathrm{H}_{12}}}{n_{0_{2}}}=\frac{x / 2}{4 x / 32}=\frac{(x) \times 32}{2 \times 4 x}=\frac{4}{1}=4: 1$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free