A moving coil galvanometer allows a full scale current of $10^{-4}\, A$. A series resistance of $2\, M\,\Omega $ is required to convert the above galvanometer into a voltmeter of range $0 -5\, V$. Therefore the value of shunt resistance required to convert the above galvanometer into a ammeter of range $0-10\, mA$ is....$\Omega $
JEE MAIN 2019, Medium
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$200 + 10^{-4}\, G = 5$
$G = -ve$
$G = -ve$
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