Where in the diagram will the electron have the greatest change in potential energy before hitting the one of the plates?

- AA
- BB
- CC
- DD

Explanation:
A charged species tends to move from place of higher potential energy to that of lower potential energy.
The direction of electric field is from left to right. This means that there is a positively charged plate on the left side, closest to A and farthest from B.
An electron being negatively charged plate always moves towards left here.
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When an inert gas is filled in the place vacuum in a photo cell, then
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(a) Photo-electric current is decreased |
|
(b) Photo-electric current is increased |
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(c) Photo-electric current remains the same |
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(d) Decrease or increase in photo-electric current does not depend upon the gas filled |
$\text{y}=\text{a}_1\sin\omega\text{t}$
$\text{y}=\text{a}_2\sin(\omega\text{t}+\in)$
$\text{y}=\text{a}_1\sin2\omega\text{t}$
$\text{y}=\text{a}_2\sin2(\omega\text{t}+\in)$
A man runs towards a mirror at a speed 15 m/s The speed of the image relative to the man is
|
(a) 15 |
(b) 30 |
(c) 35 |
(d) 20 |