A neutral spherical copper particle has a radius of $10 \,nm \left(1 \,nm =10^{-9} \,m \right)$. It gets charged by applying the voltage slowly adding one electron at a time. Then, the graph of the total charge on the particle versus the applied voltage would look like
KVPY 2019, Advanced
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$(a)$ From $V=\frac{k q}{r}$,
$q=\frac{V \cdot r}{k}=C \cdot V$
As, $q=n e$, hence graph of quersus $V$ is a step function.
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