A parallel plate air capacitor has a capacitance of $100\,\mu F$. The plates are at a distance $d$ apart. If a slab of thickness $t(t \le d)$and dielectric constant $5$ is introduced between the parallel plates, then the capacitance will be.......$\mu F$
A$50$
B$100$
C$200$
D$500$
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C$200$
c (c) Capacitance will increase but not $5$ times (because dielectric is not filled completely). Hence new capacitance may be $200$ $\mu F$.
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