Answer

Correct option: B.
(b): When the gap between the plates is completely filled with dielectric of dielectric constant $K$, then potential is
$
V=\frac{Q d}{A \varepsilon_0 K}...(i)
$
and electric field is
$
E=\frac{Q}{A \varepsilon_0 K}....(ii)
$
From equations (i) and (ii), both electric field and potential decrease.

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