MCQ
A parallel plate capacitor is charged. If the plates are pulled apart:
- AThe capacitance increases.
- BThe potential difference increases.
- CThe total charge increases.
- DThe charge and potential difference remain the same.
✓
Answer
- The potential difference increases.
Explanation:
Capacitance of a parallel plate capacitor.
$\text{C}=ε0\text{AdC}=ε0\text{Ad}$
A parallel plate capacitor is charged (battery is disconnected) then the plates are pulled apart, the capacitance decreases while the charge remains the same.
$\because$ Potentialdifference = ChargeCapacitance∵Potentialdifference = ChargeCapacitance.
$\therefore$ potential difference increases.
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