A parallel plate capacitor with air between the plate has a capacitance of $15 pF$. The separation between the plate becomes twice and the space between them is filled with a medium of dielectric constant $3.5.$ Then the capacitance becomes $\frac{ x }{4}\,pF$.The value of $x$ is $............$
JEE MAIN 2023, Medium
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$C _0=\frac{\in_0 A }{ d }=15\,pF$
$C =\frac{ K \in_0 A }{2 d }=\frac{3.5}{2} \times 15\,pF$
$=\frac{105}{4}\,pF$
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