A part of a long wire carrying a current $i$ is bent into a circle of radius $r$ as shown in figure. The net magnetic field at the centre $O$ of the circular loop is
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(c) The given circuit can be considered as follows
${B_{{\rm{loop}}}} = \frac{{{\mu _0}i}}{{2r}}\odot$
${B_{{\rm{conductor}}}} = \frac{{{\mu _0}i}}{{2\pi r}}\odot$
${B_{{\rm{net}}}} = \frac{{{\mu _0}i}}{{2\pi r}}(\pi + 1)\odot$
${B_{{\rm{loop}}}} = \frac{{{\mu _0}i}}{{2r}}\odot$
${B_{{\rm{conductor}}}} = \frac{{{\mu _0}i}}{{2\pi r}}\odot$
${B_{{\rm{net}}}} = \frac{{{\mu _0}i}}{{2\pi r}}(\pi + 1)\odot$
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