MCQ
A particle executes simple harmonic motion with a frequency $f$. The frequency with which its kinetic energy oscillates is
- A$f/2$
- B$f$
- ✓$2f$
- D$4f$
✓
Answer
Correct option: C.
$2f$
c
(c) Kinetic energy $K = \frac{1}{2}m{v^2} = \frac{1}{2}m{a^2}{\omega ^2}{\cos ^2}\omega \,t$
(c) Kinetic energy $K = \frac{1}{2}m{v^2} = \frac{1}{2}m{a^2}{\omega ^2}{\cos ^2}\omega \,t$
$ = \frac{1}{2}m{\omega ^2}{a^2}(1 + \cos 2\omega \,t)$
hence kinetic energy varies periodically with double the frequency of $S.H.M$. i.e. $2\omega $.
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