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13. oscillations — Physics STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 SciencePhysics13. oscillations1 Mark
MCQ
A particle executing simple harmonic motion has an amplitude of $6\, cm$. Its acceleration at a distance of $2 \,cm$ from the mean position is $8\,cm/{s^2}$. The maximum speed of the particle is ... $ cm/s$
  • A
    $8$
  • ✓
    $12$
  • C
    $16$
  • D
    $24$
✓

Answer

Correct option: B.
$12$
b
$A = {\omega ^2}y$

$\omega  = \sqrt {A/y}  = \sqrt {\frac{8}{2}}  = 2\,rad/sec$

Now ${v_{\max }} = a\omega  = 6 \times 2 = 12\,cm/sec$

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