A particle has simple harmonic motion. The equation of its motion is $x = 5\sin \left( {4t - \frac{\pi }{6}} \right)$, where $x$ is its displacement. If the displacement of the particle is $3$ units, then it velocity is
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(d) From the given equation, $a = 5$ and $\omega = 4$
$v = \omega \sqrt {{a^2} - {y^2}} = 4\sqrt {{{(5)}^2} - {{(3)}^2}} = 16$
$v = \omega \sqrt {{a^2} - {y^2}} = 4\sqrt {{{(5)}^2} - {{(3)}^2}} = 16$
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