A particle is executing $S.H.M.$ and its velocity $v$ is related to its position $(x)$ as $v^2+a x^2=b$, where $a$ and $b$ are positive constants. The frequency of oscillation of particle is ..........
Medium
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(b)
$v^2+a x^2=b$
$v^2=b-a x^2$
$v^2=a\left(\frac{b}{a}-x^2\right)$
Comparing it to equation
$v^2=\omega^2\left(A^2-x^2\right)$
$\omega=\sqrt{a}$
$f=\frac{\omega}{2 \pi}=\frac{\sqrt{a}}{2 \pi}$
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