A particle is executing $S.H.M.$ with total mechanical energy $90 \,J$ and amplitude $6 \,cm$. If its energy is somehow decreased to $40 \,J$ then its amplitude will become ........ $cm$
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(b)
$\frac{1}{2} m A^2 \omega^2=90 \,J$
$m$ and $\omega$ remaining same energy is reduced to $40 \,J$.
$\frac{A_1^2}{A_2^2}=\frac{9}{4}$
or $\frac{A_1}{A_2}=\frac{3}{2}$
or $A_2=4 \,cm$
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