MCQ
A particle is kept at rest at the top of a sphere of diameter $42\, m$. When disturbed slightly, it slides down. At what height $‘h’ $ from the bottom, the particle will leave the sphere ........ $m$
- A$14$
- B$28 $
- ✓$35$
- D$7 $
$h = \frac{2}{3} \times 21 = 14\,m$
but from the bottom $H = h + r = 14 + 21 = 35\,metre$
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