MCQ
A particle is moving with speed $6\,m/s$ along the direction of  $\vec A = 2\hat i + 2\hat j - \hat k,$ then its velocity is
  • A
    $(4\hat i + 2\hat j - 4\hat k)\,\,units$
  • $(4\hat i + 4\hat j - 2\hat k)\,\,units$
  • C
    $(4\hat i + 4\hat j - 4\hat k)\,\,units$
  • D
    $(2\hat i + 4\hat j - 2\hat k)\,\,units$

Answer

Correct option: B.
$(4\hat i + 4\hat j - 2\hat k)\,\,units$
b
$\overrightarrow{\mathrm{v}} =|\overrightarrow{\mathrm{v}}| \hat{\mathrm{v}} $

$=6\left(\frac{2 \hat{\mathrm{i}}+2 \hat{\mathrm{j}}-\hat{\mathrm{k}}}{3}\right) $

$=4 \hat{\mathrm{i}}+4 \hat{\mathrm{j}}-2 \hat{\mathrm{k}}$

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