MCQ
A particle is performing simple harmonic motion along $x$ -axis with amplitude $4\, cm$ and time period $1.2\, sec$. The minimum time taken by the particle to move from $x = 2\, cm$ to $x =+ 4 \,cm$ and back again is given by .... $s$
  • A
    $0.6$
  • $0.4$
  • C
    $0.3$
  • D
    $0.2$

Answer

Correct option: B.
$0.4$
b
minimum time taken by particle $=\frac{T}{6}+\frac{T}{6}$

$=\frac{T}{3}$

$=0.4 \mathrm{s}$

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