MCQ
A particle is performing simple harmonic motion with amplitude A and angular velocity ${\omega }$. The ratio of maximum velocity to maximum acceleration is
- A${\omega }$
- ✓$\frac{1}{\omega }$
- C${\omega^2 }$
- D${A\omega }$
✓
Answer
Correct option: B.
$\frac{1}{\omega }$
b
(b)$\frac{{{v_{\max }}}}{{{A_{\max }}}} = \frac{{a\omega }}{{a{\omega ^2}}} = \frac{1}{\omega }$
(b)$\frac{{{v_{\max }}}}{{{A_{\max }}}} = \frac{{a\omega }}{{a{\omega ^2}}} = \frac{1}{\omega }$
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