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Simple Harmonic Motion — JEE physics STD 12 Science — Question

CBSE BoardEnglish MediumSTD 12 ScienceJEE physicsSimple Harmonic Motion1 Mark
MCQ
A particle is performing simple harmonic motion with amplitude $A$ and angular velocity $\omega$. The ratio of maximum velocity to maximum acceleration is
  • A
    $\omega$
  • ✓
    $1 / \omega$
  • C
    $\omega$
  • D
    $A \omega$
✓

Answer

Correct option: B.
$1 / \omega$
(b) $\frac{v_{\max }}{A_{\max }}=\frac{a \omega}{a \omega^2}=\frac{1}{\omega}$

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