MCQ
In the above question, the ratio of the increase in energy of the wire to the decrease in gravitational potential energy when load moves downwards by $1 mm$, will be
- A1
- B$\frac{1}{4}$
- C$\frac{1}{3}$
- ✓$\frac{1}{2}$
✓
Answer
Correct option: D.
$\frac{1}{2}$
(d) Ratio of work done $=\frac{1 / 2 F l}{F l}=\frac{1}{2}$
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