MCQ
A particle is whirled in a vertical circle of radius $1.0\  m$ using a string with one end fixed. If the ratio of maximum and minimum tension in the string is $\frac{5}{3}$, the minimum velocity of the particle during circular motion is    ......... $ms^{-1}$
  • A
    $\sqrt {10} $
  • B
    $\sqrt {50}$
  • $10$
  • D
    $10\sqrt 5 $

Answer

Correct option: C.
$10$
c
$\mathrm{T}_{\mathrm{max}}-\mathrm{mg}=\frac{\mathrm{mv}_{\mathrm{max}}^{2}}{\mathrm{R}}$

$\mathrm{mg}+\mathrm{T}_{\mathrm{min}}=\frac{\mathrm{mv}_{\mathrm{min}}^{2}}{\mathrm{R}}$

$\frac{T_{\max }}{T_{\min }}=\frac{\frac{v_{\max }^{2}}{R}+g}{\frac{v_{\min }^{2}}{R}-g}$

$\Rightarrow \mathrm{v}_{\mathrm{m} \mathrm{in}}=10 \mathrm{m} / \mathrm{s}$

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